- #1
stacope32
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http://antoine.frostburg.edu/chem/senese/101/kinetics/faq/temperature-and-reaction-rate.shtml
According to Rule of Thumb, the reaction rate doubles when there is a 10 degree rise in temperature.
I want to determine the activation energy for a lab, but my level of study is not advanced enough for me to actually calculate rate constant, therefore I am using the rule of thumb as substitute.
I am using the rule of thumb to determine the ratio of rate constant because I don't actually know how to calculate it for gas and I have no time left for more experiments.
Using the Arrhenius equation with Ea isolated on the left side, according to the rule of thumb, ln k2/k1 will be ln 2/1, however, there is only a 0.5 degree rise in my experiment, does that mean that my reaction rate will be x0.1?I need to find a way to calculate the activation energy without actually finding rate constant as my level of study is not high enough.
The reaction is Zn + HCl = ZnCl2 + H2
The values I have access to are temperature at time intervals, gas produced over time (reaction rate).
Thanks so much!
According to Rule of Thumb, the reaction rate doubles when there is a 10 degree rise in temperature.
I want to determine the activation energy for a lab, but my level of study is not advanced enough for me to actually calculate rate constant, therefore I am using the rule of thumb as substitute.
I am using the rule of thumb to determine the ratio of rate constant because I don't actually know how to calculate it for gas and I have no time left for more experiments.
Using the Arrhenius equation with Ea isolated on the left side, according to the rule of thumb, ln k2/k1 will be ln 2/1, however, there is only a 0.5 degree rise in my experiment, does that mean that my reaction rate will be x0.1?I need to find a way to calculate the activation energy without actually finding rate constant as my level of study is not high enough.
The reaction is Zn + HCl = ZnCl2 + H2
The values I have access to are temperature at time intervals, gas produced over time (reaction rate).
Thanks so much!