Calculating Recoil Velocity from Alpha Decay

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To calculate the recoil velocity of the remaining nucleus after alpha decay, apply the conservation of momentum principle. The alpha particle's kinetic energy can be converted to velocity using the formula for kinetic energy, which allows for the determination of its momentum. Once the momentum of the alpha particle is known, it can be equated to the momentum of the recoiling nucleus to find its velocity. This approach effectively illustrates the relationship between the emitted particle and the recoil of the parent nucleus. Understanding these concepts is crucial for accurately calculating recoil velocity in nuclear decay scenarios.
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The nucleus of ^214 {Po} decays radioactively by emitting an alpha particle (mass 6.65 * 10^-27 kg) with kinetic energy 1.23 * 10^{-12} J, as measured in the laboratory reference frame.

Assuming that the {Po} was initially at rest in this frame, find the magnitude of the recoil velocity of the nucleus that remains after the decay.



I'm not even sure where to begin. Any guidance in the right direction would be appreciated.
 
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Think that the Po nucleus is a gun and the alpha particle is a bullet. The gun recoils when the bullet is fired. You can determine the recoil velocity, by applying a conservation law, what is it?

ehild
 
so i can use the kinetic energy to find velocity then use p = mv to calculate the recoil? can't believe i didnt think of it that way. thanks.
 
Always remember conservation of momentum when you hear "recoil" :smile:

ehild
 
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