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Calculating Relativistic Energy and Momentum of a Proton

  1. Feb 18, 2016 #1
    1. The problem statement, all variables and given/known data
    96m72u.png

    2. Relevant equations
    screen%20shot%2020160218%20at%2010.png

    3. The attempt at a solution
    file000.png
     

    Attached Files:

  2. jcsd
  3. Feb 19, 2016 #2
    I see you are aware that mv^2/2 is only an approximation. As a general rule of thumb, any approximation will have some limited domain of usefulness. In this case, it is only an approximation at low speeds. For high speeds you should use the exact expression.
     
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