Calculating Retained Potential Energy of a Bouncing Ball | Homework Help

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To calculate the retained potential energy of a bouncing ball dropped from a height of 1.5 m, the relevant equations include Eg = mgh and Ek = 1/2mv². The initial potential energy is calculated to be 7.5 J, but the teacher's answer indicates it should be 4.9 J, leading to confusion. Key to solving the problem is determining how high the ball bounces after the first impact, as this height affects the retained energy. Additional information about the bounce height or whether the bounce is elastic is necessary to resolve the discrepancy.
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Homework Statement


If the ball is dropped from a height of 1.5 m, how much of the potential energy, in joules, is retained
after the first bounce on the carpet?
the mass of the ball is 500g


Homework Equations



Eg = mgh
Ek = 1/2mv2
v = (2gh)-2

i think that all i need

The Attempt at a Solution


Ek which is (.5kg)(9.8)(1.5M) So the EK energy exerted is 7.5J? but my teachers answer says its 4.9 :( I am so confused help
 
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NineTHOUSAND said:

Homework Statement


If the ball is dropped from a height of 1.5 m, how much of the potential energy, in joules, is retained
after the first bounce on the carpet?
the mass of the ball is 500g

Homework Equations



Eg = mgh
Ek = 1/2mv2
v = (2gh)-2

i think that all i need

The Attempt at a Solution


Ek which is (.5kg)(9.8)(1.5M) So the EK energy exerted is 7.5J? but my teachers answer says its 4.9 :( I am so confused help

It drops from 1.5m. But how high does it bounce? Isn't the height attained after the first bounce the height you need to answer the question?
 
it bounces elastically?
i think some info is missing...
 
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