Calculating rms speed of hydrogen molecules

Click For Summary
SUMMARY

The discussion centers on calculating the root mean square (rms) speed of hydrogen molecules after a series of energy changes. Initially, the rms speed is 1800 m/s with a total translational energy of 1800 J. After 500 J of work is done on the gas and 2000 J of heat is released, the final thermal energy is calculated to be 1500 J. The correct approach involves using the equation E = (5/3)(1/2)mv^2 to find the new rms speed based on the adjusted thermal energy.

PREREQUISITES
  • Understanding of thermodynamics, specifically the first law of thermodynamics
  • Familiarity with the equation for translational kinetic energy
  • Knowledge of the properties of diatomic gases, particularly hydrogen
  • Basic algebra for manipulating equations and solving for variables
NEXT STEPS
  • Study the first law of thermodynamics and its applications in gas systems
  • Learn about the kinetic theory of gases and its relation to temperature and energy
  • Explore the derivation and application of the equation E = (5/3)(1/2)mv^2
  • Investigate the behavior of diatomic gases under varying thermal conditions
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in the behavior of gases under energy transformations.

amw2829
Messages
11
Reaction score
0

Homework Statement



The rms speed of the molecules in 1.1 g of hydrogen gas is 1800 m/s.

500 J of work are done to compress the gas while, in the same process, 2000 J of heat energy are transferred from the gas to the environment. Afterward, what is the rms speed of the molecules?

I've already solved for the total translational energy(1800 J) before more work was done to the molecules. The thermal energy was also 3000 J.

Homework Equations



E = (5/3)(1/2)mv^2



The Attempt at a Solution



Since 500 J are compressed, and 2000 J are released, the energy would then be 300 J. I tried setting this equal to the above equation, but all answers I entered were wrong.
 
Physics news on Phys.org
amw2829 said:

Homework Statement



The rms speed of the molecules in 1.1 g of hydrogen gas is 1800 m/s.

500 J of work are done to compress the gas while, in the same process, 2000 J of heat energy are transferred from the gas to the environment. Afterward, what is the rms speed of the molecules?

I've already solved for the total translational energy(1800 J) before more work was done to the molecules. The thermal energy was also 3000 J.



The Attempt at a Solution



Since 500 J are compressed, and 2000 J are released, the energy would then be 300 J. I tried setting this equal to the above equation, but all answers I entered were wrong.

300 J as final energy is wrong.
When compressing, work is done on the gas, increasing the internal energy. So 500 J is added, 2000 J heat removed.

ehild
 
ehild said:
300 J as final energy is wrong.
When compressing, work is done on the gas, increasing the internal energy. So 500 J is added, 2000 J heat removed.

ehild

1800(Initial Energy) + 500 - 2000 = 300 J

Am I missing something or does the thermal energy also play a factor.
 
The work done and the heat removed changes the thermal energy, which is 5/2 RT for one mole of a diatomic molecule. ehild
 
ehild said:
The work done and the heat removed changes the thermal energy, which is 5/2 RT for one mole of a diatomic molecule.


ehild

I took that approach and my answer was still wrong.
 
Could you show your work in detail?

ehild
 
ehild said:
Could you show your work in detail?

ehild

3000 J(thermal energyinitial) + 500 J - 2000 = E thermalfinal = 5/3(1/2)mv2
 
3000 J was the initial thermal energy . It decreased by 1500 J, the final thermal energy is 1500 J. The thermal energy is 5/3 (1/2 mv^2). So how much is 1/2 mv^2, the translational kinetic energy? How much is v, the rms speed? ehild
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
12K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
9
Views
2K