Calculating rms speed of hydrogen molecules

Click For Summary

Homework Help Overview

The discussion revolves around calculating the root mean square (rms) speed of hydrogen molecules after a series of energy transfers involving work and heat. The original poster presents initial conditions, including the rms speed and energy values, and seeks to determine the new rms speed following these changes.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the impact of work done on the gas and heat removed on the internal energy and thermal energy of the system. There are attempts to relate these energy changes to the rms speed using the equation for translational kinetic energy.

Discussion Status

Some participants have provided guidance on the relationship between work, heat, and thermal energy, while others are questioning the calculations and assumptions made regarding the energy values. There is an ongoing exploration of how these factors influence the final rms speed.

Contextual Notes

Participants note that the initial thermal energy and the effects of energy transfer are critical to understanding the problem. There is a focus on the specific energy values and their implications for the final calculations, with some uncertainty about the correct application of the relevant equations.

amw2829
Messages
11
Reaction score
0

Homework Statement



The rms speed of the molecules in 1.1 g of hydrogen gas is 1800 m/s.

500 J of work are done to compress the gas while, in the same process, 2000 J of heat energy are transferred from the gas to the environment. Afterward, what is the rms speed of the molecules?

I've already solved for the total translational energy(1800 J) before more work was done to the molecules. The thermal energy was also 3000 J.

Homework Equations



E = (5/3)(1/2)mv^2



The Attempt at a Solution



Since 500 J are compressed, and 2000 J are released, the energy would then be 300 J. I tried setting this equal to the above equation, but all answers I entered were wrong.
 
Physics news on Phys.org
amw2829 said:

Homework Statement



The rms speed of the molecules in 1.1 g of hydrogen gas is 1800 m/s.

500 J of work are done to compress the gas while, in the same process, 2000 J of heat energy are transferred from the gas to the environment. Afterward, what is the rms speed of the molecules?

I've already solved for the total translational energy(1800 J) before more work was done to the molecules. The thermal energy was also 3000 J.



The Attempt at a Solution



Since 500 J are compressed, and 2000 J are released, the energy would then be 300 J. I tried setting this equal to the above equation, but all answers I entered were wrong.

300 J as final energy is wrong.
When compressing, work is done on the gas, increasing the internal energy. So 500 J is added, 2000 J heat removed.

ehild
 
ehild said:
300 J as final energy is wrong.
When compressing, work is done on the gas, increasing the internal energy. So 500 J is added, 2000 J heat removed.

ehild

1800(Initial Energy) + 500 - 2000 = 300 J

Am I missing something or does the thermal energy also play a factor.
 
The work done and the heat removed changes the thermal energy, which is 5/2 RT for one mole of a diatomic molecule. ehild
 
ehild said:
The work done and the heat removed changes the thermal energy, which is 5/2 RT for one mole of a diatomic molecule.


ehild

I took that approach and my answer was still wrong.
 
Could you show your work in detail?

ehild
 
ehild said:
Could you show your work in detail?

ehild

3000 J(thermal energyinitial) + 500 J - 2000 = E thermalfinal = 5/3(1/2)mv2
 
3000 J was the initial thermal energy . It decreased by 1500 J, the final thermal energy is 1500 J. The thermal energy is 5/3 (1/2 mv^2). So how much is 1/2 mv^2, the translational kinetic energy? How much is v, the rms speed? ehild
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
12K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
9
Views
2K