Calculating/Simulating Vehicle Braking Force

In summary, the conversation discusses the forces on a vehicle traveling on an inclined plane, particularly the negative or braking force caused by gravity. The equation for calculating this force is F = mg sin(ang). The conversation also considers the role of tires and friction in the force calculation, as well as the use of brakes to generate a torque that compensates for both gravity and static friction. The conversation concludes by stating that momentum does not need to be considered in these calculations.
  • #1
Gazzoo
5
0
Hi All,

I know this type of question has been asked many times but I need help to clarify for myself if I'm doing the right thing. So here goes...

I am trying to simulate/understand the forces on a vehicle as it is traveling on a road. In particular as it is traveling up hills. So if I have my equations correct the primary negative or braking force would be gravity and would be tangential to the inclined plane. This would be calculated using

F = mg sin(ang)

So for an inclined plane/road at 10 deg, and a 3000kg vehicle the tangential gravitational force would be

F = 3000 x 9.81 x sin(10) = 5110.47 N

So is it correct to assume that this force is applied at the wheel contact surface which may have a radius of say 0.2m producing a torque of

T = F x R = 5110.47 * 0.20 = 1022.09 Nm

So in order to mimic this same force/torque using the car brakes they would need to generate a total negative braking torque of the same amount right?

Do I need to bother with speed/momentum in any manner when trying to calculate this braking force as well as the vehicle is traveling up the incline?

Thanks for your help!
 
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  • #2
first part is correct, it is mg*sin(ang)

you are talking about a car, a car has tires and tires cause friction
if the car is moving without sliding (I assume this is the case here) you need to consider static friction too, it is static because the contact point of the tire does not move relative to the inclined plane.

the breaks produce a torque that compensates for both of those
and let life stay as simple as it is do not consider any momentum in any of these cases :smile:
 
  • #3


I would say that your calculations and understanding of the forces on a vehicle are correct. The primary negative or braking force on a vehicle traveling up an inclined plane would indeed be gravity, which can be calculated using the equation F = mg sin(ang). This force would be applied at the wheel contact surface and would produce a torque, which can also be calculated using T = F x R, where R is the radius of the wheel. In order to mimic this same force using the car brakes, they would need to generate a negative braking torque of the same amount.

However, it is important to consider other factors such as speed and momentum when calculating the braking force on a vehicle. The vehicle's speed and momentum will affect how quickly it can come to a stop and the amount of force required from the brakes. Additionally, other forces such as air resistance and friction from the road surface should also be taken into account.

In order to accurately simulate the forces on a vehicle traveling on an inclined plane, it may be necessary to use more complex equations and models that take into account these other factors. It is always important to consider all variables and factors when conducting scientific simulations or calculations.
 

FAQ: Calculating/Simulating Vehicle Braking Force

1. How do you calculate vehicle braking force?

To calculate the braking force of a vehicle, you will need to know the mass of the vehicle, the coefficient of friction between the tires and the road surface, and the deceleration rate. The equation for calculating braking force is: Braking Force = Mass x Deceleration Rate. The deceleration rate can be determined by dividing the vehicle's initial velocity by the stopping distance.

2. What factors affect the braking force of a vehicle?

There are several factors that can affect the braking force of a vehicle. The mass of the vehicle, the coefficient of friction between the tires and the road surface, the condition of the tires, and the condition of the braking system can all impact the braking force. Additionally, external factors such as road conditions, weather, and the gradient of the road can also affect the braking force.

3. How does the coefficient of friction affect vehicle braking force?

The coefficient of friction is a measure of the grip between the tires and the road surface. The higher the coefficient of friction, the more grip the tires have on the road, resulting in a higher braking force. Conversely, a lower coefficient of friction can result in reduced braking force and longer stopping distances.

4. Can vehicle braking force be simulated?

Yes, vehicle braking force can be simulated using computer software. These simulations take into account various factors such as vehicle mass, tire conditions, road conditions, and braking system performance to accurately calculate the braking force and stopping distance of a vehicle. Simulations can be useful for predicting the performance of a vehicle in different scenarios and for optimizing braking systems.

5. How can vehicle braking force be improved?

Improving the braking force of a vehicle can be achieved by ensuring the tires are in good condition and have a high enough coefficient of friction, regularly maintaining and replacing worn brake pads and rotors, and keeping a safe following distance to allow for proper braking. Additionally, installing advanced braking systems such as anti-lock brakes can also improve braking force and overall safety.

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