Calculating Speed after Impulse of 6 Ns

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SUMMARY

The discussion focuses on calculating the final velocity of a 2 kg object that experiences an impulse of 6 Ns while moving at an initial speed of 4 m/s. The correct application of the impulse-momentum theorem reveals that the final velocity is 7 m/s, derived from the equation 2v - 2(4) = 6. Participants clarified the direction of impulse and the correct formulation of momentum change, emphasizing the importance of correctly identifying initial and final states in momentum calculations.

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  • Understanding of Newton's Second Law of Motion
  • Familiarity with the impulse-momentum theorem
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  • Knowledge of momentum concepts (mass and velocity)
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Homework Statement


A 2kg object is moving to the right with a speed of 4 m/s when it experiences an impulse of 6 Ns .


Homework Equations



mv+mv=mv

The Attempt at a Solution


Since the impulse is just the change in momentum I put in 2(4)+2v=6 so wouldn't v be -1?
 
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hi kerbyjonsonjr! :wink:

(btw, which direction is the impulse?)
kerbyjonsonjr said:
Since the impulse is just the change in momentum …

yes that's correct :smile:
… I put in 2(4)+2v=6 so wouldn't v be -1?

what is 2(4)+2v=6 supposed to be? :confused:

the impulse is the difference between the momentum after and before …

try again :smile:
 
got it now! thanks for the help! I messed up. It should have been the final minus the initial. So it's 2v-2(4)=6 which gets me v= 7 m/s. Thanks for the help!
 

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