Calculating Spring Constant: Why 1.5 cm Isn't the Correct Measurement

AI Thread Summary
A spring scale stretches 10 cm under a 15 N force, leading to a spring constant calculation of k = 1.5 N/cm. The correct distance between adjacent 1.0 N marks on the scale is approximately 0.67 cm, not 1.5 cm. This is derived from the formula F = kx, which shows that for 1 N of force, the displacement x equals 1 N divided by the spring constant. It’s crucial to maintain proper unit handling throughout calculations to avoid confusion. Clear documentation of each step in calculations is recommended for accuracy.
RedBurns
Messages
24
Reaction score
2
A spring scale is stretched 10 cm when a force of 15 N is applied to it. How far apart should adjacent 1.0 N marks be on the scale?

Why would 1.5 cm not be correct?

Force= Spring Constant* Change in spring from rest
15n=k*10 cm
k=1.5
 
Physics news on Phys.org
Wouldn't it be 0.66 cm? If there are 15 marks within 10 centimeters, there should be a mark every 2/3 of a centimeter. I may be reading this question wrong, though.
 
RedBurns said:
A spring scale is stretched 10 cm when a force of 15 N is applied to it. How far apart should adjacent 1.0 N marks be on the scale?

Why would 1.5 cm not be correct?

Force= Spring Constant* Change in spring from rest
15n=k*10 cm
k=1.5

For starters, watch the units! You are dividing N by cm! NOT a good habit to get into. The good news is, since you are using this k to calculate a distance in cm you can get away with it.

Otherwise:
F = kx
15 N = k(10 cm)
k = 15 N/10 cm = 1.5 N/cm.

Now, set F = 1 N. (Since F is linear in x, this will be the separation between 1 N marks.)

F = kx
1 N = (15 N/cm)x
x =1 N/(15 N/cm) = 0.66667 cm.

My tip to all my students, anyways, is to ALWAYS write out your work, even if it seems easy enough to do in your head. (Perhaps especially when!)

-Dan
 
your right. I had everything flipped in my head
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top