Calculating Spring Constant with a Mass on a Compressed Spring - Simple Solution

AI Thread Summary
A massless spring compressed to 71% of its relaxed length is analyzed with a mass of 0.150 kg placed on top, which takes 1.10 seconds to reach the peak of its trajectory. The spring constant is to be calculated using the energy conservation principle, but the initial approach incorrectly used the spring's new length instead of the compression distance. The correct compression distance should be 0.310 m multiplied by 29% (the amount it is compressed), not the new length. This clarification helps ensure the correct application of the formula for calculating the spring constant. Accurate calculations are essential for determining the spring constant in this scenario.
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A massless spring of length .310 m is compressed to 71.0 % of it's relaxed length, and a mass M=.150 kg is placed on top and released from rest. The mass then travels vertically and it takes 1.10 s for the mass to reach the top of its trajectory. Calculate the spring constant, in N/m. Use g= 9.81 m/s^2. Assume that the time required for the spring to reach its full extension is negligible.

I really have no idea how to do this problem. I tried using conservation of energy and solving for k, I'm not sure if I even have all of the forms of energy
(1/2)kx^2= (1/2)mv^2
(1/2)k(.2201)^2= (1/2)(.150)(10.78^2)
to get 360.0 N/m , which wasn't right


Any help would be appreciated. Thanks
 
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When you multiply .310 m by 71%, what you're getting is the length of the spring when compressed. The x in the equation you're using is the distance it's compressed, not its new length.

Does that do it?
 
Yes.. that's what I was doing wrong. Thanks
 
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