Calculating Stream Impact Distance from Container with Bernouilli's Equation

  • Thread starter Thread starter CollectiveRocker
  • Start date Start date
  • Tags Tags
    Liquid Mechanics
AI Thread Summary
To calculate the impact distance R from a container with a hole, Bernoulli's Equation can be used to determine the exit velocity of the fluid, applying Torricelli's law. The velocity of the fluid exiting the hole is given by v = (2gh)^(1/2), where h is the height of the water above the hole. Once the exit velocity is known, projectile motion equations can be employed to find R, factoring in the height from the hole to the ground. The time of flight must be calculated to complete the kinematic equations for determining R. Overall, the process involves using fluid dynamics to find velocity and then applying kinematics for the trajectory.
CollectiveRocker
Messages
137
Reaction score
0
If I have a container, filled with water, and a hole is cut in the side at some distance h from the top, how do I go about finding the distance R from the foot of the container that the stream will impact the floor? Do I use Bernouilli's Equation: P1 + ½ pv12 + pgy1 = P2 + ½ pv22 + pgy2 Where P = pressure at depth h, p = density of fluid, and y1 & y2 are = two heights about surface. Or is there another way?
 
Physics news on Phys.org
1.By Benoulli, you find the velocity by which the fluid leaves the container (Torricellis law).
2. Use projectile motion to determine R (you'll need to know how high above the ground the hole is)
 
If v = (2gh)^1/2, then we turn to use the kinematic equations. y = H(height from top water level to floor)-h(height of top water level to hole in side of container), we know g, all we're missing is the original velocity, time, and acceleration. Is there something I'm missing?
 
Your not missing anything. If you have the velocity, the rest is just simple kinematics.
 
I get R = ((2gh)^(1/2))*t, is this correct?
 
As long as "t" is the time it takes to reach the ground, yes.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top