Calculating String Tension in Rotational Motion: m, r, v0, g

AI Thread Summary
In a scenario where an object of mass "m" is whirled in a horizontal circle, the tension in the string just before it breaks can be calculated using the formula T=[(Mg)^2 +((M(v)^2)/R)^2]^(1/2). The discussion emphasizes understanding the conditions leading to the string breaking, particularly the role of centripetal force and tension. Participants are encouraged to work through the problem independently and identify specific areas of difficulty. Key considerations include the relationship between speed, radius, and gravitational force. Ultimately, grasping these concepts is crucial for accurately determining string tension in rotational motion.
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An object of mass "m" is whirled with increasing speed in a horizontal circle. if the string breaks with v0 determine the tension in the string just before the string breaks using the terms m,r(radius of circle), v0, and g.
 
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This really belongs in the homework section. Also, you have to try to work it out yourself and tell us where you're having trouble. Show us what you've done so far.
 
f=mv^2/r awwww coeme onnn! You know this!
 
the answer is: T=[(Mg)^2 +((M(v)^2)/R)^2]^(1/2) but i can't get it
 
first think about why does the string breake?
then try to answer when does the string breake
then,
think about the centripetal force and the tension just before the string breaks
try to do something with these two
 
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