Calculating Takeoff Speed for Jumbo Jet: m/s^2

  • Thread starter Thread starter ghoff36
  • Start date Start date
  • Tags Tags
    Jet Speed
AI Thread Summary
To calculate the lowest constant acceleration needed for a jumbo jet to reach a takeoff speed of 360 km/h from a 1.69 km runway, the relevant equations include those for kinematics, specifically relating speed, acceleration, and distance. The conversion of 360 km/h to meters per second is necessary for accurate calculations. An attempt at solving the problem should be presented to facilitate assistance. Resources like physics forums can provide additional guidance. Understanding these principles is crucial for solving similar physics problems effectively.
ghoff36
Messages
4
Reaction score
0

Homework Statement



A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the lowest constant acceleration needed for takeoff from a 1.69 km runway? Answer in m/s^2
 
Physics news on Phys.org
What are the relevant equations for this sort of problems? Also, you need to show an attempt at solving the problem before we can help you.
 
yeah this helps a lot
 
https://www.physicsforums.com/showthread.php?t=94379
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top