Calculating Temperature Increase in Nuclear Fusion Reaction

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The discussion focuses on calculating the temperature increase of fusion reactor walls due to a 30 keV plasma energy event. The initial calculation method is correct, yielding a temperature increase of approximately 4.643 x 10^-23 K per particle. When extrapolated to a mole of plasma, the increase is about 27.962 K. The low temperature increase is attributed to the large mass of the reactor walls, which significantly dampens the effect of the plasma energy. Overall, the calculations align with expectations given the scale of the materials involved.
Dalaran
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Hi all,

I've been given an assignment to calculate the temperature increase of the fusion reactor walls in some theoretical event. It is a 30keV plasma energy in which the heat of the entire plamsa is instantaneously dropped on the wall. I can calculate volume of the wall and have the given density as well as specific heat.

My approach:

Cp = specific heat (J/kg*K) = 460
rho = density (kg/m3) = 7600
V = volume (m3) = 29.61
P = plasma energy (eV) = 30,000
and q is conversion of eV to J (1.602x10-19)

T increase = (P * q) / (Cp * rho * V)

I end up some ridiculously low # of x10-24 degree celcius (or K) increase. I know that these are using very little mass at any given time, but with a plasma temperature of ~3X108 I expected some reasonable value. Is what I am doing correct or am I way out in left field with my thinking?

Appreciate the help.
 
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Hi,
This is extremely late, but whatever.
30 KeV refers to energy per particle in the plasma. Your formula is correct on a per particle basis, and it gives 4.643*10^-23 K increase per particle of plasma. Extrapolating to, for example, on mole of plasma, gives 27.962 K increase. These numbers are small because youre heating a few hundred tons of wall material.
 
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