Calculating the Area of a Kite in a Figure

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Homework Statement


The lengths of the two perpendicular supporting rods are 80.0cm and 105.0 cm. The lengths of the two shorter sides are 50.0 cm and the lengths of the two longer sides are 85.0cm.
The supporting rods are drawn with a bolded line in the figure.

Homework Equations


Calculate the area of the kite in the figure and give the answer in units meters squared.
The supporting rods are drawn with a bolded line in the figure.

The Attempt at a Solution


we divide the kite into two triangles, the up triangle and lower triangle
Akite=Aup+Adown

Aup= 0.8*0.3/2 = 0.12m2
Adown= 0.8*0.75 / 2 = 0.3m2

Akite= 0.12+0.3 = 0.42m2
 

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chawki said:

Homework Statement


The lengths of the two perpendicular supporting rods are 80.0cm and 105.0 cm. The lengths of the two shorter sides are 50.0 cm and the lengths of the two longer sides are 85.0cm.
The supporting rods are drawn with a bolded line in the figure.

Homework Equations


Calculate the area of the kite in the figure and give the answer in units meters squared.
The supporting rods are drawn with a bolded line in the figure.

The Attempt at a Solution


we divide the kite into two triangles, the up triangle and lower triangle
Akite=Aup+Adown

Aup= 0.8*0.3/2 = 0.12m2
Where did the 0.3 come from? Apparently you are saying that the altitude of the upper triangle is 30 cm or 0.3 m. How did you get that?
chawki said:
Adown= 0.8*0.75 / 2 = 0.3m2
Here you are apparently saying that the altitude of the lower triangle is 75 cm of .75 m. How did you get that?
chawki said:
Akite= 0.12+0.3 = 0.42m2
 
Mark44 said:
Where did the 0.3 come from? Apparently you are saying that the altitude of the upper triangle is 30 cm or 0.3 m. How did you get that?
Here you are apparently saying that the altitude of the lower triangle is 75 cm of .75 m. How did you get that?

we try to find the heigh of the upper triangle, we have
0.42+h2=0.52
h2=0.52-0.42
h=0.3m

and then it's easy to find the area of that upper triangle..
 

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OK - your answer in post #1 looks fine.
 

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