Calculating the Boat's Velocity After a Simultaneous Dive: Momentum Conservation

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To determine the boat's velocity after the child and father dive, apply the conservation of momentum principle. The child's momentum is 80 kg·m/s east, while the father's momentum, calculated from his mass and diving angle, is approximately 90 kg·m/s south. Since the boat was initially motionless, the total momentum before the dives is zero, meaning the boat must move in the opposite direction of the combined momentum of the child and father. By calculating the resultant vector from the two momentum components, the boat's velocity can be determined. This scenario illustrates the conservation of momentum in a system where external forces are negligible.
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Homework Statement


A 40 kg child and her 75 kg father simultaneously dive from a 100 kg boat that is initially motionless. The child dives horizontally toward the east with a speed of 2m/s, and the father dives toward the south with a speed of 1.5m/s at an angle of 37degrees above the horizontal. Determine the magnitude and direction of the velocity of the boat along th mater's surface immediately after their dives.

I have no idea about the question, please help! thanks
 
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Take the component of the man's momentum on the horizontal plane. Now the man's momentum and the child's momentum are perpendicular to each other. According to conservation of momentum the resultant of these two momentum should be the momentum of the boat.
 
it's a collision so momentum is conserved, and initial speed of the whole system is 0. This is like a grenade exploding, the kinetic energy of the system should increase but the momentum is conserved.
Add the vectors together and you should get 0, since the original momentum was 0.
 
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