Calculating the Capacitance of a Semicircular Dielectric Capacitor

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To calculate the capacitance of a semicircular dielectric capacitor, the setup involves two circular metal plates with a radius of 0.55 m, separated by a 2.5 mm gap. Half of the gap is filled with a dielectric medium of constant 16.3, while the other half is filled with air. The capacitance can be approached by treating the two sections as separate capacitors, one with the dielectric and one without. The initial confusion about whether to treat them in series or parallel is clarified, with the suggestion to attempt a parallel configuration first. This method will help accurately determine the overall capacitance in nanofarads (nF).
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Homework Statement


http://nplq1.phyast.pitt.edu/res/westwolf/bookauthor/Capacitors/circle.jpg

We use two circular metal plates of radius 0.55 m and thickness 8.7 mm to build a capacitor. We leave a gap of 2.5 mm between the plates and fill half of the space between the plates with a medium with dielectric constant 16.3 and leave the other half filled with air. What is the capacitance of this capacitor in units of nF?

Homework Equations



C=((eplison zero)*(dielectric constant)*(area))/2

The Attempt at a Solution



I'm not sure how to start this problem. I was thinking, maybe divide the area in half, one with the dielectric and one without it, and treat it as two separate capacitors in a series, but can that be done?
 
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Sounds reasonable to me - but wouldn't it be two caps in PARALLEL?
 
I'll try the parallel attempt first
 

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