Calculating the Dipole Moment of LiBr

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The discussion revolves around calculating the dipole moment of LiBr, given its bond length of 255 pm and assuming an ionic bond. The initial calculation attempted to use the charge of an electron multiplied by the bond length in meters, resulting in an incorrect answer. It was pointed out that the calculation was in coulomb-meters (C*m) rather than the required Debye (D) units. The need for unit conversion to arrive at the correct dipole moment was emphasized. Ultimately, the focus is on ensuring the correct units are used for the dipole moment calculation.
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Dipole Moment!

Ok I'm very tired because I've spent the past 50 minutes trying to figure out a problem that should take only 5. Someone please just take 2 minutes of your time to save me 20 more minutes. THis is a simple problem yet I cannot do it on my own, without my textbook and with what vague description there is on the internet.

"The bond length of LiBr is 255 pm. What would be the dipole moment, in D, of this compound assuming an ionic bond?"

I've tried using this equation of multiplying the charge of an electron by the bond length (in picometers) converted to meters. I got the wrong answer: 4.086 x 10 ^ -29.

That is, I multiplied "1.60217646 × 10-19 coulombs" by "255 x 10 ^ -29"
 
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Yup, that's the right answer. Don't spend any more time on this; the answer sheet probably made a mistake.
 


Edit Forget my comment.
 


stacker said:
"The bond length of LiBr is 255 pm. What would be the dipole moment, in D, of this compound assuming an ionic bond?"
You calculated the answer in C*m units, but they wanted it in units of D. You need to convert the units.
 
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