Calculating the field strength of an alternating magnetic field

AI Thread Summary
To calculate the magnetic field strength of a solenoid, the user needs to ensure proper unit conversion, as the length is given in centimeters and the current in amps, while the desired output is in kA/m. The formula for the magnetic field strength (H) in a solenoid is H = (n * I), where n is the number of turns per unit length and I is the current in amps. The user has a solenoid of 7 cm length and 5 turns, which requires converting the length to meters for accurate calculations. Additionally, the frequency of the applied current may affect the calculations if considering AC effects. Proper attention to units and formulas is essential for accurate results.
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I have a solenoid copper coil 7 cm lengths, 5 turns, r =0.75; applied current 145 V; 0.73 A; frequency 1.10 MHz and I'm still not able to calculate the magnetic field strength in kA/m. Can you help me?

I tried a number of formulas, but I just don't get it. :confused:
Please point me in the right direction.
 
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Well, what were the formulas you tried?

Also, did you pay attention to units? Note that the length is given in cm, and current in amps, but the units of the answer kA per metre.
 
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