Calculating the Force Needed for Constant Velocity of a 15 kg Crate on a Floor

AI Thread Summary
To slide a 15 kg crate across the floor at a constant speed, a horizontal force must overcome the force of kinetic friction. The coefficient of kinetic friction is 0.28, leading to a calculated frictional force of 41.16 N. This value rounds to 41.2 N, which is the force needed to maintain constant velocity. The calculation appears correct and is confirmed by other participants in the discussion. Therefore, a force of 41.2 N is required to slide the crate.
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Homework Statement


A 15 kg crate rests on the floor. The coefficient of kinetic friction between the crate and the floor is 0.28. How much horizontal force is needed to slide the crate across the floor at a constant speed?


Homework Equations



Fnet=ma


The Attempt at a Solution


F=MN
Mmg=.28*15 kg*9.8

41.16 N
For a final rounded answer of 41.2 N.

This answer seems plausible to me, would someone please confirm?

Thanks! :smile:
 
Last edited:
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Looks right to me.
 
Thank you!
 
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