Calculating the Mass of a Hollow Pipe Using Density and Dimensions

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To calculate the mass of a hollow pipe, the outer radius is 4.5 cm, the inner radius is 2.8 cm, and the length is 36 cm, with a density of 7.8 g/cm^3. The correct approach involves calculating the volume of the hollow section by subtracting the inner volume from the outer volume, using the formula for the volume of a cylinder. The mass can then be determined by multiplying the volume by the density and converting the result to kilograms. A misunderstanding arose regarding the addition of the inner and outer radii, which led to an incorrect calculation. The final mass should be accurately computed based on the correct volume formula.
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Homework Statement



A piece of pipe has an outer radius of 4.5cm, an inner radius of 2.8cm and length of 36cm

The density of the pipe is 7.8 g/cm^3

What is the mass of this pipe? Answer is in unites of kg.

Homework Equations



Density=mass/volume

Mass= (density)(volume)

Volume= mass/density

The Attempt at a Solution



I subtracted the volume of the hollow inside of the tube from the large radius (2.8+4.5cm) and multiplied that by the density given. Then I converted to kg by dividing by 1000. My answer came up to be appx 40 kg. But I believe I'm wrong.
 
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movsesinator1 said:
I subtracted the volume of the hollow inside of the tube from the large radius (2.8+4.5cm)...
The outer radius is given as 4.5 cm. (No need to add 2.8+4.5.)
 
Oh yeah thanks.
I thought that i had to add the radii because the diagram on the page made it seem as if the outer radius was that of only the thickness of the pipe.
 

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