Calculating the Maximum Kinetic Energy of pions

AI Thread Summary
To calculate the maximum kinetic energy of pions from a kaon decay, the rest energies of pions (π- 140 MeV, π0 135 MeV, π+ 140 MeV) and kaons (K- 494 MeV, K0 498 MeV, K+ 494 MeV) are used. The initial calculation yields 79 MeV by subtracting the total rest mass of the pions from the kaon's rest mass. However, the book states the correct answer is 74 MeV, indicating a discrepancy. The discussion highlights the importance of considering charge conservation in the decay process, suggesting an error in the initial equation. Accurate calculations must account for all relevant factors to determine the correct kinetic energy.
Kashif Iqbal
Messages
1
Reaction score
0

Homework Statement


The problem is to Use the rest energy values in table 1 to calculate the maximum kinetic energy of the pions assuming the kaon is at rest before it decays.

Rest Energies of pions are π- 140, π0 135 and π+ 140.
Rest energies of kaons K- 494, K0 498 K+ 494

Homework Equations


K+---> π0 + π- + π+

The Attempt at a Solution



494-(140+140+135) = 79MeV

In the book it says answer is 74MeV[/B]
 
Physics news on Phys.org
Hello kashif, :welcome:

There is something wrong with your relevant equation: what about charge in your decay mode ?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

Similar threads

Replies
3
Views
1K
Replies
54
Views
10K
Replies
4
Views
3K
Replies
33
Views
4K
Replies
34
Views
3K
Replies
15
Views
3K
Back
Top