Calculating the natural frequency of a piping system

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SUMMARY

The discussion focuses on calculating the natural frequency of a piping system using the formula f = C * SQRT[(E.I/M.L^4)(1+Seff/Pcr+C.(d/D)^2]. The user encounters a negative natural frequency of -0.5 i Hz, indicating an imaginary frequency, which suggests an overdamped system that does not oscillate. The negative axial force in the piping, influenced by temperature and pressure, is identified as a potential cause for this result. Participants emphasize the importance of reviewing the assumptions behind the formula to understand the implications of an imaginary frequency.

PREREQUISITES
  • Understanding of natural frequency calculations in mechanical systems
  • Familiarity with Young's modulus and its application in material science
  • Knowledge of the second moment of area and its significance in structural engineering
  • Basic principles of damping in dynamic systems
NEXT STEPS
  • Study the implications of imaginary frequencies in mechanical systems
  • Research the effects of boundary conditions on natural frequency calculations
  • Learn about the critical buckling load (Pcr) and its role in structural stability
  • Explore methods for calculating effective axial forces in piping systems under varying conditions
USEFUL FOR

Mechanical engineers, structural analysts, and anyone involved in the design and analysis of piping systems will benefit from this discussion.

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I'm calculating the natural frequency of a piping system that is spanning between two points, the formula is the square route of various terms, including the effective axial force in the piping. This is taken from a design code, see below:

f = C * SQRT[(E.I/M.L^4)(1+Seff/Pcr+C.(d/D)^2]

C = Constant dependent on boundary conditions of span
E = Youngs modulus
I = Second moment of area (piping)
M = Mass
L = Span length
Seff = Axial force in piping
Pcr = Critical buckling load
d = deflection
D = piping diameter

The axial force in the piping is negative, due to the temperature and pressure, and I'm trying to perform a conservative calculation assuming the piping is fully restrained. This results in a negative term in the square root. Is it possible to have a negative natural frequency?

The natural frequency is coming out as -0.5 i Hz (i being sqrt(-1)).

Any help or guidance appreciated. Thanks
 
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Just some quick observations:

I would say that the interpretation of the result probably depends on the assumptions made when deriving that formula.

It could be that an imaginary frequency could indicate an overdamped system which does not oscillate, but instead decays towards its equilibrium state (or diverges unphysically away from the equilibrium state, depending on the sign). It may not be possible to say just from looking at that formula.

Either you have made a mistake, or you need to study the assumptions of the derivation of that formula to understand what the imaginary frequency means in your context.
 
yeah I've been doing some reading over night, i think it might be due to the effective force being overly conservative. there will be 'feed in' to it, which will reduce the compressive force. thanks
 

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