Calculating the normalized form of a matrix

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Homework Statement



Calculate the normalized form of the matrix

1-1020
2-1011
4 0101

Homework Equations





The Attempt at a Solution


Im wondering if the normalized form of this matrix is

100nn
010nn
001nn

where n are the numbers resulting from the normalization of the matrix.

Is this correct?

Thanks a lot in advance.
 
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Jimmy84 said:

Homework Statement



Calculate the normalized form of the matrix

1-1020
2-1011
4 0101
Why are the - signs in rows 1 and 2?
Jimmy84 said:

Homework Equations





The Attempt at a Solution


Im wondering if the normalized form of this matrix is

100nn
010nn
001nn

where n are the numbers resulting from the normalization of the matrix.

Is this correct?

Thanks a lot in advance.
Assuming that you want to get to reduced row-echelon form, yes, the above is correct.
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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