Calculating the Period of an Earth Satellite

AI Thread Summary
The discussion revolves around calculating the orbital period of an Earth satellite at a height of 1.80 x 10^7 m using the formula T = SQRT(4π² * R³ / (G * Mass of the Earth)). Participants clarify that the radius must include both the Earth's radius and the satellite's height. There is confusion regarding the calculations and the proper use of scientific notation on calculators, leading to incorrect results. The correct period is stated to be 10.5 hours, as indicated by the lecturer. The conversation highlights the importance of accurate input and understanding of the formula to achieve the correct answer.
Chica1975
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Homework Statement


What is the period of an Earth satellite orbiting at a height of 1.80 x 10^7m above the surface of the earth? Use G = 6.67 x 10^-11 N.m2 Kg-2


Homework Equations



T = SQRT 4*pi^2 * R^3/G*Mass of the earth

The Attempt at a Solution


I added the Earth mass and the height and got = 5.98 x 10^24
Then I plugged everything into the equation but cannot get the answer out. I am not so great on this scientific notation addition etc calculations on the calculator.

the answer is 10.5 but I can't get it out.

PLEASE HELP!
 
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hello there,

please provide some details about your calculations and about the units of the answer.

It's 10.5 what ? (mention the units)
 
the units in the answer are hours - the answer was given by the lecturer.

I plugged in the formulae as per above and got

sqrt of 39.4784176 * 3.97471 * E33/ 1764366 =38.379 hours
 
Chica1975 said:
above the surface of the earth

It means orbit radius is not 1.80x107.

Edit: I see you posted in the meantime. Numbers you show don't make much sense, please elaborate what they are.
 
yes that is the height I multiplied the radius of the Earth and the height of satellite
 
I meant to say I added not multiplied
 
Chica1975 said:
3.97471E33/ 1764366

Neither of these numbers is correct. I guess first one should be R3 and the other one GM.
 
Borek said:
It means orbit radius is not 1.80x107.

Edit: I see you posted in the meantime. Numbers you show don't make much sense, please elaborate what they are.

I have basically looked at the formula and plugged in what it says. Radius is the radius of Earth (6.38 x 10^6) plus the height of satellite. Then the gravitational constant is given. and pi we know. and then mass of the Earth (5.98x 10^24)
 
Borek is right. Your calculations are actually very strange

As for the radius, it must be the sum of the radius of Earth + the height of the satellite
 
  • #10
then there is no way you can get that crazy E33 number ! u'll get smth around E21
 
  • #11
Chica - please explain how do you enter these numbers into your calculator. Key by key.
 
  • #12
exactly - my calculator is driving me crazy - every time I use E anything it spits out something I cannot fathom I am so over it you have no idea I have doing this for 3 hours now.
 
  • #13
I type it like this for eg the radius of the earth
(6.38 shift e (6)) + (1.80 shift e (7)) and press the equals sign
 
  • #14
radius of the Earth + height of satellite is what I meant - am frazzled! :)
 
  • #15
despite being told not to use the x10^X on my calculator - I tried it with that and I got it out. so much for my tutor being on the ball! Thanks everyone.
 
  • #16
No idea what calculator you use, most of those I know don't require something like "shift e", they have just a separate key for exponents. For example EE on TI calculators, or EXP on old Casio.
 
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