Calculating the Phase Spectrum from a Fourier Transform

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Discussion Overview

The discussion centers on the process of calculating the phase spectrum from a Fourier Transform, specifically how to identify the real and imaginary parts of a sum of functions that are Fourier Transforms. Participants explore the mathematical foundations and practical challenges involved in this process.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant references a source stating that the phase spectrum is calculated using the arctangent of the ratio of imaginary to real parts of the Fourier transform.
  • Another participant suggests that the real and imaginary parts of a sum of functions can be separated by summing the real parts and the imaginary parts individually.
  • Some participants express uncertainty about how to extract the real and imaginary parts from a Fourier transform, indicating a need for clarification.
  • A participant proposes that the real and imaginary parts of a complex function are determined similarly to those of real numbers and requests an example to illustrate the issue.
  • One participant provides a specific function and its Fourier transform, asking how to identify the real and imaginary parts from these expressions.
  • Another participant explains that the Fourier transform should be expressed in the form a + jb, where a and b are real numbers, and outlines steps to achieve this form, including the decomposition of the exponential function.
  • There is a question about how to handle the Dirac delta function in this context, with a suggestion to treat it like an ordinary real function.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the extraction of real and imaginary parts from Fourier transforms, indicating that the discussion remains unresolved with multiple viewpoints on the approach to take.

Contextual Notes

Some participants highlight that the challenges may stem more from understanding complex numbers rather than Fourier transforms themselves. There is also an indication that specific examples may be necessary for clarification.

dead_devil_66
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Hi!

I'm trying to understand how do i get the phase spectrum from a Fourier Transform. From this site

http://sepwww.stanford.edu/public/docs/sep72/lin4/paper_html/node4.html#lin4_swhfactm

this statement

"The phase spectrum is usually calculated by taking the arctangent of the ratio of imaginary to real parts of the Fourier transform."

Yeah, right. So, when i have a sum of functions that are Fourier Transforms, how do i know which is the real part and the imaginary part of the entire sum?
 
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Re[f(k)+g(k)]=Re[f(k)]+Re(g(k))

and the same with imaginary part. Does this answer the question, or I misunderstood something?
 
Petr Mugver said:
Re[f(k)+g(k)]=Re[f(k)]+Re(g(k))

and the same with imaginary part. Does this answer the question, or I misunderstood something?

it answer half of the things i asked. The unanswered part is how do i get the imaginary and the real parts of any Fourier transform?
 
I think I'm missing something. Ther real and imaginary part of a complex function are taken the same way you do for numbers... try giving an example so we can see where's the problem...
 
i have this function

[PLAIN]http://j.imagehost.org/0556/fun_ao_pre_trans_fourier.png

the Fourier transform is

[PLAIN]http://j.imagehost.org/0286/fun_ao_trans_fourier.png

now, how do i get the real and the imaginary parts??
 
Last edited by a moderator:
Ah ok, the problem is then more about complex numbers than with Fourier transforms. You have to put the Fourier transform in the form a + jb, with a and b real numbers. Then a will be the real part and b the imaginary part. You go by steps:

1) The exponential decomposes like

e^{j\theta}=\cos\theta+j\sin\theta

2) The inverse of a complex number is

\frac{1}{a+jb}=\frac{a-jb}{a^2+b^2}

3) Oh and finally recall that j^2=-1 !

Using these 3 rules, you can, with a bit of patience, write your expression like a + jb. Try it yourself, if you don't get it we'll see.
 
ok, but how do i do with the dirac function?
 
dead_devil_66 said:
ok, but how do i do with the dirac function?

Treat the delta function just like an ordinary real function.
 

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