Calculating the probability of winning the lotto

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Homework Help Overview

The discussion revolves around calculating the probability of winning the 6/49 lottery, specifically focusing on the interpretation of the probability results in terms of time until a win based on different playing frequencies.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of expected time until winning based on different frequencies of play, questioning the conversion of annual probabilities to daily or weekly contexts.

Discussion Status

Participants are engaged in clarifying the relationship between plays per win and time per win, with some offering insights into unit conversions and calculations. There is an ongoing exploration of how different playing frequencies affect the expected time until a win.

Contextual Notes

There is mention of specific assumptions regarding the number of days in a year and the frequency of play, which may influence the calculations being discussed.

trap101
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So I have a question I was going over in a textbook about calculating the probability of winning the 6/49 lotto. Which means you have to pick 6 correct numbers out of 49, order does not matter. So I got that:

P(L) = 6/49 * 5/48* 4/47 * ...* 1/44 = 1 / 13,983816

but then there is a comment afterwards that I can't figure out the solution:

"So if you were to play once a year, on the average you would win once every 13,983,816 years. If you played once per day, given that there are 364.25 days in a year,on average you would win once every 268,920 years.

How do they obtain the 268,920 years? What am I missing in being able to convert it over?

Thanks
 
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hi trap101! :smile:
trap101 said:
"So if you were to play once a year, on the average you would win once every 13,983,816 years. If you played once per day, given that there are 364.25 days in a year,on average you would win once every 268,920 years.

13,983,816 / 268,920 = 51.9999

sooo :rolleyes: … i guess they meant once a week! :wink:
 
tiny-tim said:
hi trap101! :smile:


13,983,816 / 268,920 = 51.9999

sooo :rolleyes: … i guess they meant once a week! :wink:

Thanks Tim, but I'm still not clearly getting it. So dividing those two sets of years provides me with 51.99, which I suppose means 52 weeks. I think I'm getting confused with which unit where.
 
trap101 said:
Thanks Tim, but I'm still not clearly getting it. So dividing those two sets of years provides me with 51.99, which I suppose means 52 weeks. I think I'm getting confused with which unit where.

The expected number of times you must play until you win is 13,983,816. If you played once a year, then on average you would need to wait about 13 million years until you win. If you played once per week (52 times per year) you would need to wait about 13,983,816/52 ≈ 269,000 years, etc.
 
hi trap101! :smile:

(just got up :zzz:)
trap101 said:
I think I'm getting confused with which unit where.

since you're asking about units, i'll just add to what Ray :smile: says …

the units are plays per win (or play.win-1)

the question asks about time per win,

so you multiply plays per win * time per play (= time per win) …

the lotto always has a play per win of 13,983,816

if time per play is 1 year, then time per win = 13,983,816*1 years

if time per play is 1/52 year (ie 1 week), then time per win = 13,983,816*1/52 years :wink:
 
tiny-tim said:
hi trap101! :smile:

(just got up :zzz:)


since you're asking about units, i'll just add to what Ray :smile: says …

the units are plays per win (or play.win-1)

the question asks about time per win,

so you multiply plays per win * time per play (= time per win) …

the lotto always has a play per win of 13,983,816

if time per play is 1 year, then time per win = 13,983,816*1 years

if time per play is 1/52 year (ie 1 week), then time per win = 13,983,816*1/52 years :wink:




Ahhh. Thank you gentlemen. It really comes down to documenting every aspect so I could get these unit troubles under control.
 

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