Calculating the Radius of a Rotating Coil in a Magnetic Field

  • Thread starter Thread starter buckeyes
  • Start date Start date
  • Tags Tags
    Coils Current
AI Thread Summary
Coil 1 has a radius of 5.5 cm and operates in a magnetic field of 0.17 T, while Coil 2 operates in a stronger field of 0.42 T, yet both experience the same maximum torque. The area of Coil 1 was calculated as approximately 95.03 cm². Using the torque formula t = NAIB, it was determined that the area of Coil 2 must be 38.46 cm² to maintain equal torque conditions. However, the calculation for the radius of Coil 2, derived from the area, resulted in an incorrect value of 10.99 cm. The discussion highlights a need to re-evaluate the calculations to ensure accuracy in determining the radius of Coil 2.
buckeyes
Messages
26
Reaction score
0
Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field in a setup similar to the square coil in the figure below. Coil 1 has a radius of 5.5 cm and rotates in a 0.17 T field. Coil 2 rotates in a 0.42 T field. Each coil experiences the same maximum torque. What is the radius (in cm) of coil 2?

http://www.webassign.net/CJ/21-21.gif


here is what i tried.
i found the area of the first coil by using a=(pi)r(squared) =(95.03)
next i used the formula t=NAIB for both coils. since i know they both have the same N, I, and t, i can combine the two formulas ending up with AB=ab (cap letters represent 1st coil, lowercase letters represent coil 2) i know all variables except A. now i can find A=38.46. now i can find r of the second coil using A=(pi)r(squared) i found r to be 10.99cm but this is wrong. where did i mess up?
 
Physics news on Phys.org
I believe everything looks good up to A=38.46

So the area's smaller than the other coil's area, but the radius is bigger? Check your math again
 
got it. thank you. :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top