Calculating the Rate of Change of Area Covered on a Level Surface

Incog
Messages
17
Reaction score
0

Homework Statement



A liquid is being poured onto a level surface making a circular pattern on the surface. Find the rate of change of the area covered on the surface with respect to the radius when the radius is 20cm.

Homework Equations



Surface area = (Pi)r^2

The Attempt at a Solution



Well, what's there to do? If you find the surface area, it's 1256 but what do you do after that? Only one numerical value is given so there's not much to work with. And I don't even know how the answer's supposed to look like - is it going to be in cm, cm^2...Can somebody get me started here...
 
Physics news on Phys.org
Whenever you see that RATE OF CHANGE is being asked of, then this should indicate that you should be using derivatives.

Now it is asking for rate of change of the Surface area. So find d(SA)/dt.
 
The question is asking you how quickly is the area of the puddle increasing, given that the puddle already has a radius of 20cm.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top