"Calculating the Velocity of an Arrow Hitting Hay

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To calculate the original velocity of a 1kg arrow that penetrates 47.0cm into hay with an average frictional force of 2500.0N, the work done by the friction must be determined using the formula W = fd. The work done is negative since it represents a loss in kinetic energy as the arrow comes to a stop. Applying the kinetic energy-work theorem, the equation simplifies to W = -1/2mvi^2, where vf is zero. The negative work indicates a decrease in kinetic energy, confirming that the original velocity can be calculated from the work done against friction. Understanding these principles allows for the accurate determination of the arrow's initial velocity.
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Homework Statement


A 1kg arrow hits a bail of hay and penetrates 47.0cm. The average frictional force of the hay on the arrow is 2500.0N. What was the original velocity of the arrow?


Homework Equations


Ffr = uk x Fn


The Attempt at a Solution


I'm completely lost, can someone please walk me through this?
 
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Well we know that,

W = fdcos(theta).

cos(theta) is going to go to 1 so,

W = fd.

We're given then average force and the distance so we can solve for the work done.

After you've done that I want you to think about the kinetic energy - work theorem ;)
 
is the kinetic energy-work theorem net work = change in kinetic energy?
so then, w = 1/2mvf^2-1/2mvi^2, but vf is 0 because the arrow is stopped in the hay so really w = -1/2mvi^2. does that stay negative?
 
lking226 said:
is the kinetic energy-work theorem net work = change in kinetic energy?
so then, w = 1/2mvf^2-1/2mvi^2, but vf is 0 because the arrow is stopped in the hay so really w = -1/2mvi^2. does that stay negative?

Yes, the work done is negative, because the kinetic energy decreaes (in this case all the way to zero, so that the change in kinetic energy is just the negative of how much there was to start with).
 
got it, thanks guys!
 
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