Calculating Time for a Car to Cover Distance with Acceleration

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To calculate the time it takes for a car to cover 699 meters while accelerating from rest at 3.4 m/s², the equation s = ut + (1/2)at² can be used, where s is the distance, u is the initial velocity, a is the acceleration, and t is time. The initial velocity (u) is zero since the car starts from rest. The user expressed confusion over their previous calculation, which yielded an illogical result. It is emphasized that showing effort in problem-solving is necessary for assistance. The discussion highlights the importance of using the correct formulas and units in physics problems.
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How long (s) will it take a car to cover a distance of 699 m if it accelerates from rest at a rate of 3.4 m/s^2?
 
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ashurina said:
How long (s) will it take a car to cover a distance of 699 m if it accelerates from rest at a rate of 3.4 m/s^2?
Hello ashurina. Welcome to PF !

What have you tried?

Where are you stuck?

According to the rules for Homework Help on this Forum, you need to show effort before we can help you.
 
I have tried t = v1-v2/ a however, I am stuck because it gave me a rather large number like 206 it doesn't seem logical. And thank you, I didnt realize that
 
You're equating v1=669 m.
Unit for velocity v is m/sec.
 
This is a very easy problem.
use s=ut+(1/2)at^{2}
 
Shouldn't give the PO the solution.
 

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