Calculating Time for Guys to Go from A to C in Cart

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To calculate the total time for two guys in a cart to go from Point A to C, the time from A to B is approximately 11.46 seconds, determined using the equation for an inclined plane. The velocity at Point B can be calculated using either conservation of energy or kinematic equations, as the cart accelerates from A to B. Once the velocity at B is established, it can be assumed constant for the flat distance to C to find the time taken for that segment. The discussion emphasizes the importance of understanding the transition from potential to kinetic energy and the implications of acceleration on velocity. Overall, the approach combines physics principles to solve the problem effectively.
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Homework Statement


Two guys are sitting in a cart. At point C, they jump off to avoid the cliff below.
How long in time(total) will it take the guys to go from Point A to C?
How long will it take them to roll from A to B, and from B to C?

PhysicsProblem.png

Homework Equations


t = square root[2*(l)/(g)(sinө)] <-- given equation for measuring time taken for object to go down an inclined plane

The Attempt at a Solution


Given the equation, I found that time taken from A to B is about 11.46s, using the formula and the given values: 123m, g = 9.81m/s^2, and 11 degrees. For the part where there is a flat surface, I am confused as to how to determine time. I found out velocity from A to B to be 10.69m/s using d/t. Would I be able to use this velocity and the second distance given to find time between B to C?

Is the velocity of the cart constant from point B to C, seeing that it doesn't stop when reaching the edge of the cliff?
 
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The cart is accelerating from A to B, so what you've determined is an average velocity for that leg of the journey. It won't be the velocity that the cart has when it reaches B.

To find the velocity at B you have a couple of options. Either employ conservation of energy to figure how the drop in height converts the potential energy to kinetic energy, or employ your acceleration and time in a kinematic equation to determine the velocity.

Once you have the velocity at B, assume it remains constant across the level path from B to C and work out the time to traverse it.
 
So you are saying Et = Et'
Meaning the energy before = energy after
In this case there was potential energy before w/ no kinetic, and then kinetic energy after with no potential energy.

m(g)(h) = 1/2mv^2
cancel out m and solve for v?
 
Sure. Why not try it both ways and see if you get the same result?
 
Wait I don't understand the other way you said we can approach the problem.
"employ your acceleration and time in a kinematic equation to determine the velocity." <-- how would you do this?
 
aeromat said:
Wait I don't understand the other way you said we can approach the problem.
"employ your acceleration and time in a kinematic equation to determine the velocity." <-- how would you do this?

What's the downslope acceleration of the cart? You used it to find the time to go from A to B in your first post. d = (1/2)at2
 
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