Calculating Torque & Angular Acceleration of a Current Loop

AI Thread Summary
The discussion revolves around calculating the torque and angular acceleration of a current loop in a magnetic field. The torque is determined using the formula T = m x B, where m is the magnetic moment calculated as m = IA. The magnetic moment for the given current loop is found to be 5.4 x 10^-5. Participants confirm that the Earth's magnetic field value of 4.2 x 10^-5 should be used for calculations. The conversation emphasizes the importance of correctly applying the magnetic field value in the torque equation.
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Homework Statement


A small current loop of area A = 1.5cm^2 carries current I = 3.6mA. What torque acts on it in a lab where its magnetic moment is perpendicualr to the Earth's magnetic field of
4.2 x 10^-5
(b) Find its angular acceleration if its rotational inertia about a diameter is 6.2gcm^2


Homework Equations



T = m x B
m = IA

The Attempt at a Solution


I know that m = (.015)(.0036) = 5.4 * 10^-5.

T = abs(5.4 * 10^-5) * abs(B) * Sin(PI/2)

I'm a bit confused about what B is, should I use the B for Earth's magnetic field?
 
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Yes, use the given B for the Earth's magnetic field.
 
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