Calculating Torque Part 2: Finding d

  • Thread starter Thread starter ahero4eternity
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
To determine the point where the second person lifts the board, the concept of torque equilibrium is applied, where the total clockwise torque equals the total counterclockwise torque. Given the board's length of 3.40 meters and weight of 145 N, the upward force of 60.0 N from one end creates a torque that must be balanced by the weight of the board and the force applied by the second person. The equation for torque involves the distance from the pivot point, which is crucial for finding the exact lifting point. After initial confusion, the original poster successfully solved the problem independently. Understanding torque principles is essential for accurately calculating the lifting point in this scenario.
ahero4eternity
Messages
10
Reaction score
0
[SOLVED] Torque Part 2

Two people are carrying a uniform wooden board that is 3.40 meters long and weighs 145 N.

If one person applies an upward force equal to 60.0 N at one end, at what point does the other person lift?

d = _____ meters from the end where the first person lifts




Total Torque CW = Total Torque CCW



I'm not even sure if that's the correct equation, no less where to start. Can someone get me started on the right track without giving me the answer?

Thanks.
 
Physics news on Phys.org
Nevermind, I figured it out.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top