Calculating Trebuchet Velocity: A Homework Help Guide

AI Thread Summary
The discussion focuses on calculating the velocity of a golf ball launched by a trebuchet for a physics project. The user initially calculated a velocity of 3.53 m/s, which seemed low, prompting them to reassess their approach. They utilized the energy conservation equation and a proportion to derive a final velocity of 10.742 m/s, which they believe is accurate. The user also compared their calculated launch time of approximately 3.3 seconds with manual timing, finding similar results. Overall, the calculations and methodology appear to align with the principles of physics, leading to a satisfactory conclusion.
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Trebuchet help: Calculating velocity

Homework Statement


I'm new to this site, so bear with me!
OK, so I'm doing a trebuchet for my physics project. I have done three trials with counterweights of different masses. I have all of the distances that a golf ball of mass=0.045kg has traveled. I also have the masses of the counterweights.
Just as a starting point for the first trial:
mass of the counterweight=10.937
h=0.631m

The average distance for this trial was 34.33m.



Homework Equations


PEg=mgh
KE=(1/2)mv2


The Attempt at a Solution


I've done the calculations; however, my answers were nowhere near what the velocity should be. For one trial, the mass of the counterweight was 10.937kg. I did the calculations and the velocity came out to be 3.53m/s which seemed a little slow.

Obviously, I'm doing something wrong. I wonder if it is because the mass of the golf ball needs to be taken into account somehow? Anyways, thanks in advance!

I've used the example from https://www.physicsforums.com/showthread.php?t=250335&highlight=trebuchet and I still can't get it. I don't even understand how the answer was calculated in that example.
 
Last edited:
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Well, I think I might have it! I used that example in the post I linked to in the previous post, and I just changed the values to fit my case. I did the other example to get the right answer that was provided. So, I'm assuming that my answer is correct

Here are the givens:
m1=10.937
m2=.045
h1=.076
h2=.838

I used:
m1gh1-m2gh2=(1/2)m1v12+(1/2)m2v22

And I used the proportion:
v1 .076
-- = --
v2 .838

And just solved for v2.

My final answer was 10.742 m/s which sounds correct, but I'd like to see if I made any mistakes.
 
That proportion I used, v1/v2= 0.076/0.838, what exactly is that?
 
OK, I think that solved for velocity correctly. Using the calculated velocity and the average distance traveled of the golf balls in a trial, I calculated a time of about 3.3 seconds. When I launched golf balls and manually timed it, the results were close enough.
 
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