Calculating Velocity in Simple Harmonic Motion: A Pendulum Clock Analogy

AI Thread Summary
In simple harmonic motion (SHM), the speed of a particle at half of its maximum speed occurs at a specific displacement. The discussion uses a pendulum clock analogy to illustrate this concept. At maximum displacement, the particle's velocity is zero, while at the vertical position, it reaches maximum velocity due to minimal potential energy. To find the displacement where the speed is half of the maximum, one must consider the conservation of energy between kinetic and potential forms. Understanding these principles allows for calculating the exact displacement in SHM scenarios.
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Homework Statement



Speed of particle executing simple harmonic motion with amplitude A is half of the maximum speed. At that instant, displacement of the particle is ?

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The Attempt at a Solution

 
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You have worded this question somewhat strangely but I will attempt a solution. Think of the particle under SHM as a Pendulum clock (or weight on the end of a string). If it is "ticking" then ask "what is the velocity" at these two points:

1) When it is at maximum displacement from the vertical

2) When it passes through the vertical displacement.To give a full answer one could consider its energy. The total energy is a sum of the Kinetic and Potential energy, these must always be conserved. At the maximum displacement it changes direction, therefore at some instant it must speed=0.

At the point it passes through the vertical it is the "lowest" point, so will have the minimum potential energy. Therefore it must have the maximum kinetic energy, hence maximum velocity. Therefore you must only work out where it will have half this value.
 
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