Calculating Velocity in Simple Harmonic Motion

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SUMMARY

The discussion focuses on calculating the velocity of a mass in simple harmonic motion, specifically using the equation v(t) = -vmax sin(2πft). The position of the oscillating mass is defined as x(t) = (2.3 cm) cos(11t), with a maximum velocity (vmax) of 0.25 m/s. The user initially calculated the velocity at t = 0.43s incorrectly as 0.0206 due to using degrees instead of radians in their calculations. The correct velocity at that time is confirmed to be 0.25 m/s.

PREREQUISITES
  • Understanding of simple harmonic motion concepts
  • Familiarity with trigonometric functions in radians
  • Knowledge of the relationship between frequency and angular frequency
  • Ability to manipulate equations involving sine and cosine functions
NEXT STEPS
  • Review the principles of simple harmonic motion and its equations
  • Learn about converting between degrees and radians in trigonometric calculations
  • Study the derivation and application of the velocity equation in harmonic motion
  • Explore the effects of mass and spring constant on oscillation frequency
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to simple harmonic motion.

TerikE
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Homework Statement



The position of a 49 g oscillating mass is given by x(t)= (2.3cm) cos 11t , where t is in seconds.
Determine the velocity at t = 0.43s

Where:
f= 1.75
t=0.43s
vmax=0.25 m/s

Homework Equations



I'm using v(t)= -vmax sin (2pi*f*t)

The Attempt at a Solution



Using above equation and variables I get 0.0206, which is wrong (mastering physics).

Can't figure this one out..
 
Last edited:
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Annnnd.. I was in deg and not rad.. Funny how something so small can cause such great frustration. Answer is .25
 

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