Calculating Velocity of Wave in Wood Stick and Resonance Tube

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The discussion focuses on calculating the velocity of a transverse wave in a wooden stick used in a musical instrument, which creates a standing wave amplified by a half-open resonance tube. The relationship between the lengths of the stick and the tube is established, with the tube being four times longer than the stick. Participants emphasize the importance of matching frequencies between the wood and the tube while using the correct equations for standing waves in both mediums. A proposed solution involves using the wave equation and the relationship between the wavelengths and lengths of the stick and tube. The conversation highlights the complexity of determining the values for the wave numbers in both mediums.
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Homework Statement


A certain music instrument consists of a stick of wood placed horizontally and a resonance "tube" (see attached picture, which is from the original assignment-paper) placed vertically under the stick of wood. When the wood-stick is hit, is creates a standing wave, which is amplified in the resonance "tube". The resonance "tube" is half-open (closed in botton, open in top). The music instrument is seen below:
attachment.php?attachmentid=21869&stc=1&d=1258425457.jpg


I have to calculate the velocity of the transverse wave v_stick in the wood stick.
Information I am given:
Velocity of sound: v_sound=343 m/s

The resonance tube is four times as long as the stick of wood (the distance between the triangles on the picture)

Homework Equations


For a string with a standing wave we have that:
L=n*\frac{\lambda}{2}

For a half-open resonance "tube" we have that:
L=(2n-1)\frac{\lambda}{4}

L is the length of the string (wood stick) or the air "pillar" in which the standing wave exists, n is the number of the partial-tone and lambda is the wave length.

The Attempt at a Solution



4L_{stick}=L_{tube}

I'm unsure of what i know of the wave in the resonance tube, but if I can say that the standing wave in the wood stick has n=1 and the one in the resonance tube has n=8 (see the attached picture), I get:

4\frac{lambda_{stick}}{2}=\frac{15\lambda_{tube}}{4} \Leftrightarrow 2\lambda_{stick}=\frac{15}{4}\lambda_{tube}

I know I can insert the wave eqaution v=lambda*frequency, but what I have just seems so wrong and I have thought very long time about it. I hope you are willing to help me. I'm so stuck.

Best regards.
 

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Wow, the two n's make it complicated - many different solutions depending on their values, I think.

I would have begun with the fact that the
frequency on wood = frequency in tube
and put in the conversion to wavelength on each side and then convert the wavelength to L's using those two formulas. I get an expression for the velocity that is (2n-1)*343/8m where n is the air tone number and m the wood tone number. This may be the same as you have. I don't know how you will choose m and n.
 
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