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**[SOLVED] Calculating Velocity**

A shell is fired at an elevation of 60degrees from horizontal, it needs to reach a target

Sx=15000m, Sy = 400m. What is the initial velocity of the shell?

So far I have done this...

Ax=0 Ay=-g

Vx=V cos 60 Vy=-gt+V sin 30

Sx=V cos 60 t Sy=((-gt^2)/2)+sin 30

I've tried to work from here (using Sx to find t=15000/Vcos60, then substitute that into Sy formula) but I've been getting a negative number which can't be right.

Could someone show me the working or give me any help at all?