Calculating voltmeter resistance in DC circuit

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To find the resistance of the voltmeter in a DC circuit with a 228-Ω and a 586-Ω resistor connected in series, start by calculating the equivalent resistance using the formula for resistors in series. The voltmeter reading of 24.0 V across the 228-Ω resistor allows for the application of Ohm's law to determine the current in the circuit. The current can be found from the total voltage and the equivalent resistance without the voltmeter. Once the current is established, the voltmeter's resistance can be calculated by comparing the total resistance with and without the voltmeter connected. Using Kirchhoff's loop equations can also help relate the currents and voltages in the circuit.
ztalira
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Homework Statement


initial problem: A 228 −Ω resistor and a 586 −Ω resistor are connected in series across a 90.0−V line.
A voltmeter connected across the 228 −Ω resistor reads 24.0 V . Find the voltmeter resistance.
For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?

Homework Equations


V=IR
1/Req=1/R1 +1/R2

The Attempt at a Solution


For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?
 
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The total current is going to be given by V = IR

They give you the total voltage and they give you the resistors. To find the total resistance you have to find the equivalent resistance. The resistors are connected in series, not in parallel, so what does that tell you about how to calculate the equivalent resistance?

Once you solve for the equivalent resistance and find the total current, you can use Ohm's law again and find the resistance with the voltmeter. The resistance of the voltmeter itself will then be the difference between the value of the resistance with it and the value without it.
 
ztalira said:
For Req, i got Req=228R/(2+228), R being the resistance of the voltmeter.
But after that, I'm stuck. How do I find the necessary I(current) in order to calculate the R (resistance of voltmeter).?

normally a voltmeter does not disturb a circuit parameters - but suppose it draws a current say( Iv) then the current in 228 ohm resistance will be reduced by Iv so you have two loops one smaller one through voltmeterand the 228 ohm. a larger loop is current flowing through the two resistances- one can apply Kirchhoff's loop equations to relatecurrent and voltage and resistances. that should solve your problem
 
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The first calculation is simply a voltage divider where you can determine the resulting resistance after puting the voltmeter across R1 => Rx.
Then take Rx and calculate back using the formula you use when you have two resistors in parallel and want to know the total resistance.
you don't need a current to find Rv.
except you have to calculate them. then just use the total resistance without the voltmeter and then with the voltmeter...where R1 changes to Rx.

br Chris
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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