Calculating Volume and Side Length of a Cut Cone - Is This Right

AI Thread Summary
The discussion revolves around calculating the volume and slant height of a truncated cone, specifically a container with a top radius of 10 cm and a bottom radius of 20 cm, yielding a volume of 500 cm³. The user derived the height as approximately 1.5915 cm using volume equations and then applied the Pythagorean theorem to find the slant height, resulting in approximately 10.4944 cm. They also provided a formula for the volume of the truncated cone, indicating it is the difference between the volumes of the larger and smaller cones. The user seeks validation of their calculations and inquires about a more efficient method for solving the problem. Overall, the thread highlights the complexity of calculating dimensions of a cut cone and the importance of verifying mathematical solutions.
Ryoukomaru
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This is a problem I had in a test and almost everyone got different answers for it, we discussed and well, I spotted mistakes in their solutions so I think mine is right but I wanted to check here and also ask if there is an easier/faster way to do it.

There is a container that is similar to the bottom part of a cone which is cut into half. Top radius is 10cm and bottom is 20cm. And the volume of this container is 500cm^{3}. What is the length of the slanted side ?

So what I did was, first I drew this. ;P (See attachment)

Then what I did was to write an equation for V_2 in terms of V_1 and V_T

By solving the equation for height, I got h=1.5915
Then I used Pythagoras' theorem to find the length of the slanted side and it comes to:
10^2+2h^2=s^2=>100+3.183^2=s^2=> s=10.4944

Is this correct ? And is there a formula to find the volume of this shape ?
 

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The volume of the "flower pot" section is

V = \frac {\pi h}{3} (R^2 + rR + r^2)

where R is the large radius, r is the small radius and h is the same as your x. It's simply the difference between the volume of the large cone and the small cone.
 
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