Calculating Volume Change for an Air Bubble Rising from Depth

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An air bubble with an initial volume of 1.75 cm³ at a depth of 125 m experiences pressure changes as it rises to the surface. The initial pressure is calculated to be 1326325 Pa, while the pressure at the surface is 101325 Pa. Using the formula P1*V1=P2*V2, the volume of the bubble at the surface is determined to be approximately 22.90 cm³. The calculations assume constant temperature during the ascent. The approach and calculations appear correct based on the principles of fluid mechanics.
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An air bubble has a volume of 1.75 cm3 when it is released by a submarine 125 m below the surface of a lake. What is the volume of the bubble when it reaches the surface? Assume that the temperature of the air in the bubble remains constant during ascent.

P= a+h*g*density

a=101325Pa
h=125m
g=9.8
density of freshwater=1000kg/m^3

P1*V1=P2*V2
1326325Pa*1.75cm3=101325*V2

V2=22.90cm3?

when calculate the initial pressure i get 1326325Pa so that would be the pressure under the water and the pressure above the water would just be 101325Pa?

Am i doing this right?
 
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Looks right to me.
 
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