Calculating Volume of Tetrahedron Using Triple Integral: Step by Step Guide

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Homework Statement


Set up an integral to find the volume of the tetrahedron with vertices
(0,0,0), (2,1,0), (0,2,0), (0,0,3).

Homework Equations


The Attempt at a Solution


My method of solving this involves using a triple integral. The first step is deciding on the bounds of the triple integral. If you can envision the tetrahedron in the x, y, z plane:

The base of the tetrahedron has equations: y = x/2 and y = (4-x)/2

I know the bounds for x and y:

x goes from 0 to 2
y goes from (x/2) to (4-x)/2

How do I find the bounds for z? I need an equation relating z to x and y. . .
 
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Nevermind, I figured it out. I had to find the equation of the slanted plane by taking the cross product of two points getting the normal.

Problem solved.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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