Calculating Work Done by a Constant Force on a Moving Body

AI Thread Summary
The discussion centers on calculating the work done by a constant force on a moving body, specifically a force with components Fx=3N and Fy=4N acting on a body moving from point P to point Q. The correct method involves using the dot product of the force and displacement vectors to find the work done. After calculations, it is suggested that the work done is 16 J, aligning with the provided answer options. Additionally, participants discuss the relevance of understanding the dot product in physics and its application in solving such problems. The thread also touches on exam preparation for the Physics: C Mechanics exam, indicating the problem is sourced from College Board sample questions.
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Homework Statement


I have this packet and one of the questions state:
The constant force F with components Fx=3N and Fy=4N act on a body while that body moves from the point P (x=2 m, y=6 m) to the point Q (x=14 m, y=1 m). How much does the force do on the body during this process?

the options are as follows:
a. 16 J
b. 30 J
c. 46 J
d. 56 J
e. 65 J

Homework Equations



I have the equations to find energy:
kinetic: K=(1/2)mv^2
gravitational: mgh

The Attempt at a Solution



but I'm not sure if I'm missing something. So far I have figured out you need to keep the x and y components separated and calculate each but I think I'm doing something wrong. I've gotten to Work = Force * cos(t) * change in distance but I'm just confusing myself. Help?

Also, I am taking the Physics: C Mechanics exam, what are some topics and questions that would help me prepare for it?
 
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Do you know what a dot product is?
 
I don't know what a dot product is other than its used in calculus
 
swarm17 said:
I don't know what a dot product is other than its used in calculus

It is quite a simple operation, I am sure you must have come across it in high school maths, but for a refresher...

Dot product is defined as:
<br /> a_{i} b_{j}\delta_{ij}=a_{i} b_{i}

Example:
<br /> \vec{a} = (2\hat{e}_{1} +2\hat{e}_{2} + 2\hat{e}_{3} )<br />
<br /> \vec{b} = (0\hat{e}_{1} +2\hat{e}_{2} + 4\hat{e}_{3} )<br />

then
<br /> a_{i} b_{j}\delta_{ij}= ( 2 \bullet 0) + (2 \bullet 2) + (2 \bullet 4)<br />
<br /> a_{i} b_{j}\delta_{ij}= 12<br /> <br />
 
You have the right formula. But it easier to use the dot product formula (which may be used by people that don't know calculus)

W = Fxdx+Fydy+Fzdz.

Those are the components of the forceF and the displacement d.

EDIT: TheAustrian beat me to the punch
 
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Would the answer be a. 16 J?
I used:
F=(3i+4j) N
s=(14-2i + 1-6j)
m = 12i+-5j) m
W=f•s=36-20=16J
16 J?
 
Yeah, that looks right.
 
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swarm17 said:

Homework Statement


I have this packet and one of the questions state:
The constant force F with components Fx=3N and Fy=4N act on a body while that body moves from the point P (x=2 m, y=6 m) to the point Q (x=14 m, y=1 m). How much does the force do on the body during this process?

the options are as follows:
a. 16 J
b. 30 J
c. 46 J
d. 56 J
e. 65 J

Homework Equations



I have the equations to find energy:
kinetic: K=(1/2)mv^2
gravitational: mgh

The Attempt at a Solution



but I'm not sure if I'm missing something. So far I have figured out you need to keep the x and y components separated and calculate each but I think I'm doing something wrong. I've gotten to Work = Force * cos(t) * change in distance but I'm just confusing myself. Help?

Also, I am taking the Physics: C Mechanics exam, what are some topics and questions that would help me prepare for it?
Is this problem from a practice test or is it from a current AP test ?
 
SammyS said:
Is this problem from a practice test or is it from a current AP test ?
It is from a set of free sample test questions posted on the College Board website.

swarm17, hope everything went well for you yesterday!
 
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