Calculating Work Done by Friction

[rfig08d]

Homework Statement

You are pushing a refrigerator across the floor of your kitchen. You exert a horizontal force of 297 N for 6.7 s, during which time the refrigerator moves a distance of 2.8 m at a constant velocity.

What is the work done by friction?

Homework Equations

W=fv
w=f(d/t)

The Attempt at a Solution

w=297(2.8/6.7) = 124 J.

Why is this answer incorrect?
Any info to the right direction is much help :) thanks

 

[zhermes]

your equations are wrong,
<br /> W = F \times d<br />
Your equations are for the Power, which are force times velocity.
http://en.wikipedia.org/wiki/Work_(physics)
http://en.wikipedia.org/wiki/Power_(physics)

 

[rfig08d]

Edit - Right, it'll be -FΔx.

Thanks.