C/C++ Calculation in C++: B-C && (B-A) /C - Which Answer is Right?

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The discussion centers on a C++ calculation involving the expression B-C && (B-A)/C with variable assignments A=2, B=3, and C=4. There is confusion about the result of the expression, with one participant believing the answer is 0 because the first part is negative, while others argue it should be 1 since -1 does not equate to false. The correct interpretation clarifies that in C++, only 0 represents false, and the expression evaluates to false (0). The breakdown shows that B-C results in -1 and (B-A)/C results in 0, leading to the final evaluation of -1 && 0, which is true && false, ultimately yielding a result of false (0).
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I am doing my homework regarding calculation in c++.
I am confused by the below question.
Int A=2 B=3 C=4
B-C && (B-A) /C
I think the answer is 0 because the first part is negative.
But,my friends say the answer is 1 because -1 not mean false.
I want to ask which answer is right?
Thanks.
 
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Your friend is right - -1 doesn't mean false. 0 and only 0 means false.
 
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You and your friend are both incorrect. You could easily check this by running it through a C++ compiler.

In C++, there is implicit conversion from ints to bools. && has pretty low precedence, so first the following expressions are evaluated: B - C is 3 - 4 = -1, and (B - A) / C is 1 / 4 = 0 (in integer division).
So the resulting expression is -1 && 0 which is equivalent to true && false, hence the result you get is false (0).
 
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Ah, I referred just to the small part of the post, I have not actually bothered to evaluate whole expression :shy:
 

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