Calculation max load on a scissor jack lifting a car

Click For Summary

Discussion Overview

The discussion revolves around calculating the maximum load a scissor jack must support when lifting a 6000 lb car. Participants explore the mechanics of the car's center of gravity and the impact of different jacking points on the load distribution. The conversation includes attempts to apply principles of static equilibrium and moments in various scenarios.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states the need to determine the maximum load supported by the scissor jack when lifting a 6000 lb car, mentioning the center of gravity and potential jacking locations.
  • Another participant suggests that taking moments about one of the tires should work to solve for the maximum force at each location.
  • A participant presents calculations for two cases: leaning on back wheels and leaning on side wheels, yielding forces of 4800 lb and 3000 lb, respectively.
  • There is a suggestion that the car's center of mass being closer to the front could lead to overbalancing if the back wheels are used for support.
  • One participant questions whether the maximum force would be the same in both cases if the car leans on the side wheels for both scenarios.
  • Another participant clarifies that the car leans on different wheels depending on the jacking point, prompting a challenge to prove this assertion.

Areas of Agreement / Disagreement

Participants express differing views on the jacking scenarios and the resulting forces, indicating that there is no consensus on the maximum load calculations or the mechanics of the car's balance during lifting.

Contextual Notes

The discussion includes assumptions about the car's center of mass and the geometry of the jacking points, which may not be fully resolved. The dependency on specific configurations and the lack of visual aids in some posts contribute to the uncertainty.

vpatel28
Messages
4
Reaction score
0

Homework Statement



I have to determine the max load a scissor jack must support when lifting a 6000lb car. I know where the center of gravity is acting and the potential locations (distances from the center of gravity) the car will be jacked up. I know the max force is less than 6000 lb.

Homework Equations





The Attempt at a Solution



I tried taking the moments about one of the tires and setting them equal to zero to solve for the max force at each location, but I know I'm doing something wrong.
 
Physics news on Phys.org
Welcome to PF!

Hi vpatel28! Welcome to PF! :wink:
vpatel28 said:
… I tried taking the moments about one of the tires and setting them equal to zero to solve for the max force at each location, but I know I'm doing something wrong.

That should work :smile:

show us what you got!​
 
I've attached a diagram of the geometry of the car. The more I think about the problem, I feel like I need to know which two tires the car will lean on for each case. Inspection tells me that it will lean on the two side tires for both cases.

Do I want to take the moment about one of the tires that car is leaning on? If I do that I get the following:

Case 1 - Lean on Back wheels
(6000)(8 ft) + -F(10) = 0
F= 4800 lb

Case 2 - Lean on Side Wheels
(-6000)(3) + (F)(6) = 0
F = 3000 lb

I'd appreciate any help in directing me in the right direction
 
vpatel28 said:
I've attached a diagram of the geometry of the car.

erm :redface: … noooo! :rolleyes:
Do I want to take the moment about one of the tires that car is leaning on? If I do that I get the following:

Case 1 - Lean on Back wheels
(6000)(8 ft) + -F(10) = 0
F= 4800 lb

Case 2 - Lean on Side Wheels
(-6000)(3) + (F)(6) = 0
F = 3000 lb

Difficult to be sure without seeing a diagram,

but that certainly looks ok! :smile:
 
Sorry about that. Here is the attachment with the diagram
 

Attachments

vpatel28 said:
I've attached a diagram of the geometry of the car. The more I think about the problem, I feel like I need to know which two tires the car will lean on for each case. Inspection tells me that it will lean on the two side tires for both cases.

ok, from the diagram the wheels are 12 ft apart front-to-back, and 6 ft apart side-to-side.

The jack points are 2ft behind or in front of the nearest wheel.

The c.o.m. is 4ft behind the front wheels and 8ft in front of the back wheels.
Case 1 - Lean on Back wheels
(6000)(8 ft) + -F(10) = 0
F= 4800 lb

Case 2 - Lean on Side Wheels
(-6000)(3) + (F)(6) = 0
F = 3000 lb

Yes, those equations are fine, except that in case 1, if the c.o.m. is nearer the front, won't the car overbalance onto the side?
 
If the the car leans on the side wheels for both cases then isn't the max force the same in both cases?
 
vpatel28 said:
If the the car leans on the side wheels for both cases …

It doesn't … it leans on the front wheels for a back jacking point, and on the side wheels for a front jacking point …

can you prove that? :wink:
 

Similar threads

Replies
17
Views
7K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
Replies
13
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K