I Calculation of daily solar insolation

AI Thread Summary
The discussion focuses on calculating daily solar insolation for a specific location and date, yielding a result of 3.39E7 J/day.m2, which differs from online calculators that suggest 2.65E7 J/day.m2. Participants note that the discrepancy may be due to not accounting for albedo, which affects energy reflection. Clarifications reveal that the calculations are intermediate steps and do not represent final energy available at the surface, as real-world factors like site conditions and weather must be considered. The need for a comprehensive survey to obtain accurate results is emphasized. Accurate solar insolation calculations require consideration of various environmental factors.
jones123
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Hi all,

I'm trying to calculate the daily solar insolation (integrated solar irradiances from sunrise to sunset) for a given location and day of the year. For latitude 43.2° and April 15th, I get:

H0 = (solar constant * scale factor for intra annual variation of sun-earth distance * 86400 seconds/pi) * (cos(latitude) * cos(declination) * sin(hour angle sunset) + (hour angle sunset * pi/180)*(sin(latitude)*(sin(declination))

or with numbers:

H0 = ((1368*0.99226178414418)*(86400/pi))*(cos(43.2°)*cos(9.6423°)*sin(99.1805°)+(99.1805°*pi/180)*sin(43.2°)*(sin(9.6423°)) = 3.39E7 J/day.m2

However, when I try to check the result with online calculators, they say the result should be 2.65E7 J/day.m2 ...

Can anyone please check and help me out if and what I am doing wrong? It would be of very great help!

Thank you!
 
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I can't say I entirely follow your calculations, but the end result difference looks in the ballpark of what you'd get if you corrected for albedo - which you don't seem to have done.
 
Bandersnatch said:
I can't say I entirely follow your calculations, but the end result difference looks in the ballpark of what you'd get if you corrected for albedo - which you don't seem to have done.
Hi, calculations were based on Part 4: Irradiation Calculations | ITACA:

upload_2017-7-17_13-51-47.png
 
jones123 said:
However, when I try to check the result with online calculators, they say the result should be 2.65E7 J/day.m2 ...
What calculators are these? I'm getting 3.39E7 out of wolfram alpha.
 
Bandersnatch said:
if you corrected for albedo
What albedo?
 
sophiecentaur said:
What albedo?
Having no context for the question, I assumed the calculations were for energy available at the surface at some location, which must take into account the amount of energy reflected. The context provided later has shown that this is but an intermediary step, and such effects are taken account for later on.
 
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Bandersnatch said:
Having no context for the question, I assumed the calculations were for energy available at the surface at some location, which must take into account the amount of energy reflected. The context provided later has shown that this is but an intermediary step, and such effects are taken account for later on.
So it's not something that you could use for a general calculation. The 'real' answer must depend on the actual site, weather and time of year. A survey would be needed, I suppose.
 
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