Calculus 2 Find the volume problem

hvidales
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Homework Statement



Find the volume: y=x, y=0, x=2, x=4; about x=1

Homework Equations



Washer method V= ∏∫ (R)^(2)-(r)^(2) dy

The Attempt at a Solution


0 to 4 is my a to b**

∏∫(from 0 to 4) of (1-4)^(2)-(1-y)^(2) dy

∏∫(from 0 to 4) of 9-(1-2y+y^(2)) dy

∏∫(from 0 to 4) of 8 + 2y - y^(2) dy

∏[8y+y^(2)-y^(3)/3](from 0 to 4)

∏[32+16-64/3]=80∏/3


That is my answer but I want to make sure that I got it correct. Thanks in advance!
 
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Hey people. So I reworked it and i got 76pi/3. Is this correct?
 
I got 24∏. With rotations about the x-axis it is usually easier to use cylindrical shells. It's much harder with washers, I don't even want to think about what you'd do for that. With cylindrical shells the integral would be from 0 to 4 of 2∏∫(x-1)x dx.
 
Hey I ended up getting it. Thanks for taking the time to work it out. :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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