Calculus II - Series and Convergence

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SUMMARY

The series defined by the summation Σ n/(2n+1) from n=1 to infinity diverges. The divergence test, also known as the nth term test for divergence, indicates that if the limit of the terms does not equal zero, the series diverges. In this case, the limit approaches 1/2, confirming divergence. It is crucial to note that a limit of zero does not guarantee convergence; further analysis is required in such cases.

PREREQUISITES
  • Understanding of series and convergence concepts
  • Familiarity with the divergence test (nth term test for divergence)
  • Basic knowledge of limits in calculus
  • Ability to differentiate between sequences and series
NEXT STEPS
  • Study the comparison test for series convergence
  • Learn about the ratio test for determining convergence
  • Explore the integral test for series convergence
  • Investigate the concept of absolute convergence in series
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators looking for clarification on common misconceptions regarding series divergence and convergence tests.

GreenPrint
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Homework Statement



Determine if the series

inf
Sigma n/(2n+1)
n=1

converges

Homework Equations





The Attempt at a Solution



When i did this I originally I thought I would just apply the divergence test

lim n/(2n+1) =/= 0
n->inf

there fore I thought by the divergence test the series diverges but I guess sense the limit is defined to be 1/2 it converges...

I'm confused... I think I may be over complicating this but by the divergence test shouldn't this series diverge sense the limit does not equal zero?

Thanks for any help
 
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GreenPrint said:
... but by the divergence test shouldn't this series diverge sense the limit does not equal zero?

Yes, that's correct. It's more commonly called the nth term test for divergence.
 
GreenPrint said:

Homework Statement



Determine if the series

inf
Sigma n/(2n+1)
n=1

converges

Homework Equations





The Attempt at a Solution



When i did this I originally I thought I would just apply the divergence test

lim n/(2n+1) =/= 0
n->inf

there fore I thought by the divergence test the series diverges but I guess sense the limit is defined to be 1/2 it converges...

I'm confused... I think I may be over complicating this but by the divergence test shouldn't this series diverge sense the limit does not equal zero?
Thanks for any help

The bolded part is correct. Since you took the limit of the summand and received 1/2, the limit diverges. If the sum converges its limit is equal to 0.

However, the converse of the statement is not true. Don't fall into the trap of thinking the sum converges if the limit is equal to 0. If you obtain a limit of 0, you need to resort to a different method to determine if the sum converges.
 
hm thanks i think i got it mixed up and it asked me if the sequence converges which it does lol
 
GreenPrint said:
hm thanks i think i got it mixed up and it asked me if the sequence converges which it does lol

No it doesn't. It diverges. You just showed this using your test. Or was that a typo?

And it's a series, not a sequence.
 
ya i got it and understand now i got a different part mixed up and stuff
 

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