Calculus problem regarding Thermodynamics HW (entropy for C2H5OH at 348K)

AI Thread Summary
The discussion revolves around calculating the entropy of C2H5OH at 348K using a specific equation. The user has the entropy value at 298K as 160.7 J/K and a constant pressure heat capacity of 111.46 J/K. They are confused about how to apply the integration equation provided for entropy calculation. A hint was given to break down the integral from 0 to T into two parts, which the user plans to apply. The conversation highlights the challenges faced in thermodynamic calculations and the importance of understanding integration in this context.
densephysicist
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Summary:: Seems simple but has me stumped...

[Thread moved from a technical forum, so no Homework Template is shown]

Hello! I am struggling to use an equation given to me. To provide some context, I am trying to work out the entropy for C2H5OH at 348K.

Using provided tabulated data, the entropy (S) for C2H5OH at 298K is 160.7 [J/K].

I have also been given the specific heat capacity at constant pressure (111.46 [J/K]) and have been instructed to assume that it is independent of temp.

I simply cannot understand how to use the equation given to me...

S(T) = (integration sign with limits of 0 to T) Cp / T (derivative dash) * dT(deriv dash)

Any help is greatly appreciated.
 
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densephysicist said:
Summary:: Seems simple but has me stumped...

[Thread moved from a technical forum, so no Homework Template is shown]

Hello! I am struggling to use an equation given to me

Hint:
$$\int_0^{T_2} = \int_0^{T_1} + \int_{T_1}^{T_2}$$
 
Thanks George, I'll try to apply your hint
 

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